Final answer:
The correct separation minima for an F-18 following a B757 during an ILS approach to a full stop is 6 miles (Option D), according to FAA guidelines, to ensure safety from wake turbulence.
Step-by-step explanation:
The question refers to air traffic control separation minima in aviation, specifically during an Instrument Landing System (ILS) procedure. When sequencing aircraft for approach, different types of aircraft are categorized into wake turbulence categories because larger aircraft produce significant wake turbulence that can affect the following aircraft. The Boeing 757 is known for producing strong wake turbulence, and thus, when it is followed by a smaller aircraft, such as an F-18 fighter jet (categorized as lighter), increased separation is required.
According to the Federal Aviation Administration (FAA) guidelines, the required separation minima between a heavy aircraft category such as a B757 and a smaller, lighter category aircraft like an F-18 on final approach for ILS is 6 miles. This ensures that the wake turbulence from the heavy has dissipated enough to not affect the following light aircraft. Therefore, the correct answer to this question is D) 6 miles.