9.0k views
3 votes
Find the expression for the sum to (n-1) terms when sum of nth term of a series is Sn= 17n - 3n^2

ii find a and d

User ChuckieDub
by
8.5k points

1 Answer

3 votes

Final answer:

The expression for the sum to (n-1) terms of a series is -3n^2 + 23n - 20. The values of a and d cannot be determined without additional information about the series.

Step-by-step explanation:

The given expression for the sum of the nth term of a series is Sn= 17n - 3n^2.

To find the expression for the sum to (n-1) terms, we can substitute (n-1) for n in the given expression, which gives us:

Sn-1 = 17(n-1) - 3(n-1)^2

Simplifying this expression further, we get:

Sn-1 = 17n - 17 - 3(n^2 - 2n + 1)

Sn-1 = 17n - 17 - 3n^2 + 6n - 3

Sn-1 = -3n^2 + 23n - 20

Therefore, the expression for the sum to (n-1) terms is -3n^2 + 23n - 20.

To find the values of a and d, we need more information about the series. Please provide additional context or equations related to the series to determine these values.

User Dmitry Polyanitsa
by
8.7k points

Related questions