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If the kinetic energy of the 40kg box is 784 J, what is the velocity before it strikes the ground?
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If the kinetic energy of the 40kg box is 784 J, what is the velocity before it strikes the ground?

User Rigdonmr
by
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1 Answer

11 votes

Answer:

Step-by-step explanation:


KE=(1)/(2)mv^2


784=(1)/(2)(40)v^2


784=20v^2


39.2=v^2


v=6.26m/s

User Alexander Kachkaev
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