Question

If a=under root s(s-a)(s-b)(s-c) then the value of a, when a =3 b =4c = 5 and s =a+b+c by 2

Answer 1

6

Explanation:

Here it's given that ,

`\sf\red{\longrightarrow} A=√(s(s-a)(s-b)(s-c))`

Also ,

`\sf\red{\longrightarrow} s =(a+b+c)/(2)`

And we need to find out the value of A , when

• a = 3
• b = 4
• c = 5

So , on substituting the respective values to find s we have ,

`\sf\red{\longrightarrow} s =(3+4+5)/(2)=(12)/(2)=\bf{6}`

Now let's find out A as ,

`\sf\red{\longrightarrow} A = √(6(6-3)(6-4)(6-5)) \\`

`\sf\red{\longrightarrow}A =√(6 * 3 * 2 * 1)\\`

`\sf\red{\longrightarrow} A = √(3^2 * 2^2 *1^2)\\`

`\sf\red{\longrightarrow}A = 3*2\\`

`\sf\red{\longrightarrow}\boxed{\qquad \blue{\bf A = 6 \qquad}}`