Question

A nurse is preparing to administer mannitol 0.2g/kg IV bolus over 5 min as a test dose to a client who has severe oliguria. The client weighs 198 lbs. What is the amount in grams the nurse should administer? (round to a whole number)

Answer 1

To determine the mannitol dose for a client with oliguria who weighs 198 lbs, convert the weight to kilograms and then multiply by the dosage rate, resulting in an 18g dose when rounded to the nearest whole number.

Step-by-step explanation:

The student has asked how to calculate the amount in grams of mannitol to administer to a client who has severe oliguria and weighs 198 lbs. To determine the dosage, we first convert the client's weight from pounds to kilograms, knowing that 1 kg equals 2.2 lbs. Once we have the weight in kilograms, we multiply by the dosage rate of 0.2g/kg. Since mannitol is administered as a test dose in this scenario, we want to ensure accuracy in dosing.

First, convert 198 lbs to kilograms:
198 lbs × (1 kg / 2.2 lbs) ≈ 90 kg. Next, calculate the dosage for mannitol:
90 kg × 0.2g/kg = 18g.
Round to a whole number, the nurse should administer 18 grams of mannitol.