Question

Anna Maria is budgeting a vacation. She does not want to spend

any more than $500. If she plans to spend $325 for travel and
camping, and she budgets $20 for each meal. How many meals,
can she afford on this budget? Use the inequality to help solve
the problem:
07 meals
8 meals
O9 meals
10 meals
500 325+20x

Answer 1

Anna Maria can afford a maximum of 8 meals on her budget.

Step-by-step explanation:

To determine how many meals Anna Maria can afford on her budget, we can set up an inequality equation. Let x represent the number of meals.

According to the problem, Anna Maria plans to spend $325 on travel and camping, and budgets $20 for each meal.

The inequality can be written as: 325 + 20x ≤ 500.

To solve for x, we can subtract 325 from both sides of the inequality: 20x ≤ 175.

Then divide both sides by 20: x ≤ 8.75.

Since we can't have a fraction of a meal, the maximum number of meals Anna Maria can afford on her budget is 8 meals.