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Graph quadratic equation y=-2x^2+8x-12

User Damonkashu
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1 Answer

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The graph of the function represented by the equation y = -2x² + 8x - 12 is attached

How to graph the function represented by the equation

From the question, we have the following parameters that can be used in our computation:

y = -2x² + 8x - 12

The x-coordinate of the vertex of the above function is

x = -b/2a

So, we have

x = -8/(2 * -2)

x = 2

The y-coordinate is

y = -2(2)² + 8(2) - 12

y = -4

So, the vertex is (2. 6)

The axis of symmetry is the x-coordinate of the vertex

So, we have

x = 2

The y-intercept is when x = 0

So, we have

y = -2(0)² + 8(0) - 12

Evaluate

y = -12

Because the leading coefficient is negative, the function has a maximum vertex

Lastly,

The domain is the set of all real values, and the range is (-∞, -12]

The graph is attached

Graph quadratic equation y=-2x^2+8x-12-example-1
User Vkatsitadze
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