200k views
5 votes
Graph quadratic equation y=-2x^2+8x-12

User Damonkashu
by
8.8k points

1 Answer

6 votes

The graph of the function represented by the equation y = -2x² + 8x - 12 is attached

How to graph the function represented by the equation

From the question, we have the following parameters that can be used in our computation:

y = -2x² + 8x - 12

The x-coordinate of the vertex of the above function is

x = -b/2a

So, we have

x = -8/(2 * -2)

x = 2

The y-coordinate is

y = -2(2)² + 8(2) - 12

y = -4

So, the vertex is (2. 6)

The axis of symmetry is the x-coordinate of the vertex

So, we have

x = 2

The y-intercept is when x = 0

So, we have

y = -2(0)² + 8(0) - 12

Evaluate

y = -12

Because the leading coefficient is negative, the function has a maximum vertex

Lastly,

The domain is the set of all real values, and the range is (-∞, -12]

The graph is attached

Graph quadratic equation y=-2x^2+8x-12-example-1
User Vkatsitadze
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories