Answer:
1.62 × 10⁻²⁴ J
Step-by-step explanation:
Step 1: Given and required data
- Frequency of this radiation (ν): 2.45 × 10⁹ Hz (2.45 × 10⁹ s⁻¹)
- Planck's constant (h): 6.63 × 10⁻³⁴ J.s
Step 2: Calculate the energy (E) of this electromagnetic radiation
We will use the Planck-Einstein's relation.
E = h × ν
E = 6.63 × 10⁻³⁴ J.s × 2.45 × 10⁹ s⁻¹ = 1.62 × 10⁻²⁴ J