Answer:
f ’= 3019.8 Hz
Step-by-step explanation:
This is an exercise of the Doppler effect, that is, of the relative movement of the source (s) and the observer (o)
in the case of the source and the observer approaching, if they move away the signs are exchanged
let's calculate
f ’= 2500
f ’= 2500
f ’= 3019.8 Hz