Final answer:
To print all the prime numbers in an interval, use a loop to iterate through the numbers, check if each number is prime, and print it if it is. Here's an example code snippet to help you.
Step-by-step explanation:
To print all the prime numbers in an interval, you can follow these steps:
- Take input for the starting and ending points of the interval.
- Use a loop to iterate through all numbers in the interval.
- Check if each number is prime by dividing it by all numbers from 2 to its square root.
- If the number is divisible by any number other than 1 and itself, it is not prime.
- If the number is not divisible by any other number, it is prime, so print it.
Here's an example code snippet:
#include <iostream>
#include <cmath>
using namespace std;
bool isPrime(int n) {
if (n <= 1)
return false;
for (int i = 2; i <= sqrt(n); i++) {
if (n % i == 0)
return false;
}
return true;
}
int main() {
int start, end;
cout << "Enter the starting point: ";
cin >> start;
cout << "Enter the ending point: ";
cin >> end;
cout << "Prime numbers in the interval are: ";
for (int i = start; i <= end; i++) {
if (isPrime(i))
cout << i << " ";
}
return 0;
}