Question

A 0.14 kg baseball moving at 23.00 m s is slowed to a stop by a catcher who exerts a constant force of 370 N How long does it take this force to stop the ball Incorrect Your answer is incorrect s How far does the ball travel before stopping

Answer 1

(A) The time taken for the ball to stop is 8.7 x 10⁻³ s

(B) The distance traveled by the baseball before stopping is 0.3 m

Step-by-step explanation:

Given;

mass of the baseball, m = 0.14 kg

velocity of the baseball, v = 23 m/s

force exerted on the baseball by the catcher, F = 370 N

(A) The time taken for the ball to stop;

`F = ma = (mv)/(t) \\\\t = (mv)/(F) \\\\t = (0.14 * 23)/(370) \\\\t = 8.7* 10^(-3) \ s\\\\t = 8.7 \ ms`

(B) The distance traveled by the baseball before stopping is calculated as;

acceleration of the ball,
`a = (v)/(t) = (23)/(8.7* 10^(-3)) = 2643.678 \ m/s^2`

Distance traveled, s;

s = ut + ¹/₂at²

s = (23)(8.7 x 10⁻³) + ¹/₂(2643.678)(8.7 x 10⁻³)²

s = 0.2001 + 0.1001

s = 0.3 m