The final balanced equation is: 10H2O + 2S2O3 2- + Cl2 -> 4SO4 2- + 20H+ + 2Cl- .
Balancing the Redox Reaction using the Half-Reaction Method:
Step 1: Identify Oxidation and Reduction:
S2O3 2- is oxidized to SO4 2-.
Oxidation half-reaction: S2O3 2- -> SO4 2- + 8e-
Cl2 is reduced to Cl-.
Reduction half-reaction: Cl2 + 2e- -> 2Cl-
Step 2: Balance the charges in each half-reaction:
Oxidation half-reaction: 5H2O + S2O3 2- -> 2SO4 2- + 10H+ + 8e- (add 8 H+ to balance O and 10H+ to balance charge)
Reduction half-reaction: Cl2 + 2e- -> 2Cl-
Step 3: Balance the number of electrons transferred:
Multiply the oxidation half-reaction by 2:
10H2O + 2S2O3 2- -> 4SO4 2- + 20H+ + 16e-
The number of electrons transferred in both half-reactions must be equal.
Therefore, the final balanced equation is:
10H2O + 2S2O3 2- + Cl2 -> 4SO4 2- + 20H+ + 2Cl-