Final answer:
For children without galactosemia, their genotypes can be heterozygous (Aa) or homozygous dominant (AA). These genotypes indicate the absence of galactosemia, an autosomal recessive disorder that requires two recessive alleles to be present (aa) for the disease to manifest. The correct option is a) Heterozygous
Step-by-step explanation:
For children who do not have galactosemia, the possible genotypes for this trait are either heterozygous or homozygous dominant. Galactosemia is an autosomal recessive disorder, meaning that it manifests only when an individual has two copies of the recessive allele (homozygous recessive). Therefore, the correct answers are:
- Heterozygous (Aa)
- Homozygous dominant (AA)
A child with either of these genotypes will not display symptoms of galactosemia. A child with the genotype homozygous recessive (aa) would have the disorder. There is no such thing as 'no inheritance for this trait,' as all individuals have some combination of alleles for the genes related to galactosemia. The correct option is a) Heterozygous