Question

A person standing on a balcony throws an object upward with an initial speed of 7 m/s. The object comes down, missing the balcony, and strikes the ground 2 sec later. How high is the balcony?

a) 6.15 meters
b) 8.8 meters
c) 10.05 meters
d) 12.3 meters

Answer 1

To solve for the height of the balcony, we can use the equations of motion for projectile motion. Using the given values of the initial velocity and time, we can calculate that the balcony is 5.6 meters above the ground.

Step-by-step explanation:

To solve this problem, we can use the equations of motion for projectile motion. When an object is thrown upward, its vertical displacement can be determined using the equation: h = v0t - (1/2)gt2, where h is the height, v0 is the initial velocity, t is the time, and g is the acceleration due to gravity (approximately 9.8 m/s2).

Given that the initial velocity is 7 m/s and the time it takes for the object to strike the ground is 2 seconds, we can plug these values into the equation to solve for the height:

h = (7 m/s)(2 s) - (1/2)(9.8 m/s2)(2 s)2 = 14 m - 19.6 m = -5.6 m.

Since the height cannot be negative in this context, we can conclude that the balcony is 5.6 meters above the ground.