Question

What is the energy of a quantum of light with a frequency of 4.31 x 10^14 Hz?

a) 1.0 x 10^-19 J
b) 4.31 x 10^-14 J
c) 2.86 x 10^-19 J
d) 1.0 x 10^19 J

Answer 1

To find the energy of a quantum of light with a frequency of 4.31 x 10^14 Hz, use Planck's equation, resulting in an energy of 2.86 x 10^-19 J. The correct option is (c).

Step-by-step explanation:

The energy of a quantum of light, or photon, can be calculated using Planck's equation, which relates the energy (E) of a photon to its frequency (ν) through the Planck constant (h). The equation is E = hν.

For a frequency of 4.31 x 10^14 Hz, the energy is calculated by multiplying this frequency by Planck's constant (6.626 x 10^-34 J-s):

E = (6.626 x 10^-34 J-s)(4.31 x 10^14 Hz) = 2.86 x 10^-19 J

Therefore, the correct answer is (c) 2.86 x 10^-19 J.