Question

Gold was mined in California and divided into 1.5 kg pieces. Each piece of gold was a perfect cube 8.1 cm tall. What was the density of the gold?

a) 0.030 g/cm³
b) 1.5 g/cm³
c) 1.125 g/cm³
d) 0.125 g/cm³

Answer 1

To find the density of gold, you divide its mass in grams by its volume in cubic centimeters. The provided information states the density of gold is 19.3 g/cm³, which you can verify by doing the calculation with a gold cube that is 8.1 cm in height and has a mass of 1.5 kg.

Step-by-step explanation:

The question is asking to calculate the density of gold given that it has been divided into perfect cubes each weighing 1.5 kg and measuring 8.1 cm in height. Density is defined as the mass divided by the volume, and it is expressed in grams per cubic centimeter (g/cm³). The density of gold, from provided data, is known to be 19.3 g/cm³. To verify, we can calculate the volume of a cube (V) with an edge length (l) by using the formula V = l³, which for a cube that is 8.1 cm tall would be V = 8.1 cm * 8.1 cm * 8.1 cm. After calculating the volume, we can then find the density by dividing the mass (m) given in kilograms (which should be converted to grams) by the calculated volume (V).