Question

What is the magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge?

Use E= kq/r² and k = 9.00 x 10⁹ N.m² / C².
A. 1.9 x 10¹⁰ N
B. 5.6 x 10¹¹ N
C. 4.2 x 10⁹ N
D. 5.5 x 10¹² N

Answer 1

The magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge is 5.5 x 10¹⁲ N/C, calculated using Coulomb's law with given values.

Step-by-step explanation:

The magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge is calculated by using the formula E = kq/r², where k is Coulomb's constant (9.00 x 10⁹ N.m² / C²), q is the charge (0.0035 C), and r is the distance from the charge (0.0075 m). Plugging these values into the formula, we get:

E = (9.00 x 10⁹ N.m² / C²) x (0.0035 C) / (0.0075 m)²

E = (9.00 x 10⁹) x (0.0035) / (0.00005625)

E = 5.5 x 10¹⁲ N/C

Therefore, the correct answer is D. 5.5 x 10¹⁲ N/C.