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Consider babies born in the "normal" range of 37–43 weeks gestational age. a paper suggests that a normal distribution with mean μ = 3,500 grams and standard deviation σ = 725 grams is a reasonable model for the probability distribution of the continuous numerical variable x = birth weight of a randomly selected full-term is the probability that the birth weight of a randomly selected full-term baby exceeds 7 pounds?

User J Slick
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Final answer:

To find the probability that the birth weight of a randomly selected full-term baby exceeds 7 pounds, we need to convert the weight to grams, calculate the z-score, and look up the probability using a standard normal distribution.

Step-by-step explanation:

To find the probability that the birth weight of a randomly selected full-term baby exceeds 7 pounds, we need to convert 7 pounds to grams. There are 453.592 grams in a pound. So, 7 pounds is equal to 3175.144 grams.

Next, we need to calculate the z-score for 3175.144 grams using the mean and standard deviation provided. The formula for calculating the z-score is: z = (x - μ) / σ, where x is the value we want to convert, μ is the mean, and σ is the standard deviation.

Once we have the z-score, we can look up the corresponding probability using a standard normal distribution table or calculator.

User Valli
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