Question

Collin has $1.27 in quarters, nickels, and pennie’s. he has twice as many quarters as pennie’s. he has 11 coins total. how many of each does he have?

Answer 1

Collin has 2 quarters, 7 nickels, and 2 pennies.

Step-by-step explanation:

Let's solve this problem step-by-step to find the number of quarters, nickels, and pennies that Collin has.

Let's assume that Collin has x pennies. Since he has twice as many quarters as pennies, he will have 2x quarters.

Now, let's calculate the total value of all the coins. The value of each quarter is 25 cents, so the total value of the quarters is 25 * 2x = 50x cents. Similarly, the value of each penny is 1 cent, so the total value of the pennies is 1 * x = x cents.

The total value of all the coins is given as $1.27. Since 1 dollar is equal to 100 cents, we can write the equation as 50x + x = 127. Solving this equation, we get 51x = 127, which gives us x = 127/51 = 2.49.

Since the number of coins should be a whole number, we can round down x to 2. Therefore, Collin has 2 quarters, 2 pennies, and since he has a total of 11 coins, he must have 11 - 2 - 2 = 7 nickels.