Final answer:
To calculate the theoretical yield of iron, start with the given moles of Fe2O3 and apply the stoichiometric ratio from the balanced equation. The theoretical yield of iron from 0.300 mole of Fe2O3 is 0.600 mole of Fe.
Step-by-step explanation:
The question involves a stoichiometry calculation within the subject of Chemistry. It's a calculation of the theoretical yield in moles of iron, using the balanced chemical equation Fe2O3 + 3C → 2Fe + 3CO. We start with the given amount of Fe2O3 in moles and use the stoichiometric ratios to find the amount of Fe produced.
To find the theoretical yield of iron in moles, we will follow this process:
- Use the provided molar mass of Fe2O3, which is 159.70 g/mol, to convert the grams of Fe2O3 to moles.
- Using the stoichiometric ratio from the balanced equation, which in this case is 2 mol Fe / 1 mol Fe2O3, calculate the theoretical yield of iron in moles.
Based on the balanced equation, for every 1 mole of Fe2O3, 2 moles of Fe are produced. Since the question starts with 0.300 mole of Fe2O3, through stoichiometry, we can multiply this by the ratio (2 mol Fe / 1 mol Fe2O3) to find the theoretical yield of iron.
The calculation would be: (0.300 mol Fe2O3) × (2 mol Fe / 1 mol Fe2O3) = 0.600 mol Fe. This is the theoretical yield of iron.