Question

A charged particle is located in an electric field where the magnitude of the electric field strength is 2.0x10³.newtons per coulomb. If the magnitude of the electrostatic force exerted on the particle is 3.0x10⁻³newton, what is the charge of the particle?

Answer 1

The charge of the particle is 1.5x10⁻¶ C, calculated using the formula q = F/E where F is the electrostatic force and E is the electric field strength.

Step-by-step explanation:

The question involves calculating the charge of a particle based on the electrostatic force exerted on it and the strength of the electric field it is placed in. The relationship used to determine the charge is derived from the formula of electrical force, F = qE, where F is the force, q is the charge, and E is the electric field strength. Given that the magnitude of the electric field strength is 2.0x10³ N/C and the electrostatic force on the particle is 3.0x10⁻³ N, the charge q can be found by rearranging the formula to q = F/E.

Therefore, the charge q of the particle is:

q = F/E = (3.0x10⁻³ N) / (2.0x10³ N/C) = 1.5x10⁻¶ C.