Final answer:
The bag's velocity after falling for 2.0 seconds from a hovering helicopter is 19.6 m/s when calculated with the kinematic equation for objects in free fall: v = at, with acceleration due to gravity (9.8 m/s²).
Step-by-step explanation:
The question is asking for the velocity of a bag 2.0 seconds after it is dropped from a hovering helicopter. To find the velocity, we can use one of the kinematic equations that relates velocity, acceleration, and time:
v = vo + at
Where v is the final velocity, vo is the initial velocity, a is the acceleration (9.8 m/s2 for objects in free fall due to gravity), and t is the time. Since the initial velocity (vo) of the bag is zero (as it is dropped and not thrown), the equation simplifies to:
v = at
Thus, the bag's velocity after 2.0 seconds is:
v = (9.8 m/s2) × (2.0 s) = 19.6 m/s
The bag will have a velocity of 19.6 m/s after falling for 2.0 seconds, assuming that air resistance is negligible.