118k views
1 vote
Suppose P(X) = .35 and P(Y) = .40. If P(X|Y) = .28, what is P(Y|X)? A) (.28)(.35)/.40 B. (.28)(.40)/.35 C. (.35)(.40)/.28 D) (.28)/.40 E) (.28)/.35

User Salavert
by
8.0k points

1 Answer

1 vote

Final answer:

To find P(Y|X), use Bayes' theorem: P(Y|X) = (P(X|Y) * P(Y)) / P(X). Plugging in the given values, Y|X = 0.32.

Step-by-step explanation:

To find P(Y|X), we can use Bayes' theorem. Bayes' theorem states that P(Y|X) = (P(X|Y) * P(Y)) / P(X).

In this case, we are given that P(X|Y) = 0.28, P(X) = 0.35, and P(Y) = 0.40. Plugging these values into the formula, we get:

P(Y|X) = (0.28 * 0.40) / 0.35 = 0.32.

Therefore, the probability that Y occurs given that X has occurred is 0.32.

User Sayboras
by
7.8k points