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A 2.00-L plastic bottle contains air at a pressure of A person squeezes the bottle, resulting in a pressure of

What is the new volume of the container?

User Skurt
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1 Answer

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Final answer:

Physics problem involving Boyle's Law applied to a 2.00-L bottle to find a new volume after pressure change, but can't be solved without more information on initial and final pressures.

Step-by-step explanation:

The given scenario falls under the subject of Physics, specifically in the field of gas laws, which describes the behavior of gases under different conditions. Assuming this is a problem about ideal gases, we can apply Boyle's Law which states that the pressure of a gas multiplied by its volume is constant, provided the temperature and amount of gas remain unchanged.

If a 2.00-L bottle containing air at a certain pressure is squeezed, resulting in a new pressure, the new volume of the container can be determined using the relationship P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 is the new pressure. To find the new volume V2, rearrange the formula to V2 = (P1V1) / P2.

However, the question seems to have missing information about the initial and final pressures. Without these values, it is not possible to calculate the new volume precisely. It would be necessary for the student to provide the specific pressure values to proceed with this problem.

User Ardesco
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