191k views
0 votes
suppose p(x) = .35 and p(y) = .40. if p(x|y) = .28, what is p(y|x)? (a) (.)(.)/ . (b) (.)(.)/ . (c) (.)(.) /. (d) . /. (e) . /.55

User Kenco
by
8.3k points

1 Answer

4 votes

Final answer:

Using Bayes' theorem, the conditional probability P(Y|X) is calculated as (P(X|Y) × P(Y)) / P(X), which equals 0.32.

Step-by-step explanation:

The student is asking about the relationship between various probability conditions for two events, X and Y. In particular, they have given that P(X) = 0.35, P(Y) = 0.40, and P(X|Y) = 0.28, and they want to find P(Y|X). To find this, we use Bayes' theorem, which relates the conditional probabilities of two events:

P(Y|X) = (P(X|Y) × P(Y)) / P(X)

Substituting the known values:

P(Y|X) = (0.28 × 0.40) / 0.35 = 0.32

Therefore, the conditional probability P(Y|X) is 0.32.

User Vpz
by
7.0k points