Question

A 6.92 L sample of water contains 0.175 g of calcium ions. Determine the concentration of calcium ions in ppm if the density of the solution is 1.00 g/mL. DET V= 6.921 = 6720 ml A) 25.3 ppm B) 36.5 ppm C)52.3 ppm D) 13.2 ppm E) 12.7 ppm

Answer 1

To determine the concentration of calcium ions in ppm, convert the volume of water to milliliters, calculate the mass using density, and apply the ppm formula. The calculation yields a concentration of 25.3 ppm.

Step-by-step explanation:

To calculate the concentration of calcium ions in ppm, we must first convert the volume of water from liters to milliliters and then use the density to find the mass of the water sample. Since 1 L = 1000 mL and the density of water is given as 1.00 g/mL, we can find the mass of the water sample by multiplying the volume in milliliters by the density. After finding the mass of the water sample in grams, we can then use the following formula to determine the concentration in parts per million (ppm):

Concentration (ppm) = (mass of solute in grams / mass of solution in grams) x 106

Using the provided data:

• Volume of water = 6.92 L
• Density of solution = 1.00 g/mL
• Mass of calcium ions = 0.175 g

First, convert liters to milliliters:

6.92 L x 1000 mL/L = 6920 mL

Then, calculate the mass of the water sample using the density:

6920 mL x 1.00 g/mL = 6920 g

Finally, calculate the concentration in ppm:

Concentration (ppm) = (0.175 g / 6920 g) x 106

Concentration (ppm) = 25.3 ppm

So the concentration of calcium ions in the water sample is 25.3 ppm, which corresponds to option A.