Final answer:
To find the amount of NaCl in a 296 mL sample of a 355 ppm solution, use the ratio 355 mg NaCl per 1000 mL to calculate that approximately 105 mg of NaCl would be present in the sample.
Step-by-step explanation:
To determine how many mg of NaCl are present in a 296 mL sample of a solution with a concentration of 355 ppm NaCl, we can use a proportional calculation. Since 355 ppm means there are 355 mg of NaCl in every liter (1000 mL) of water, we can set up a ratio to find the amount in 296 mL:
355 mg NaCl / 1000 mL water = X mg NaCl / 296 mL water
Solving for X gives us:
X = (355 mg NaCl × 296 mL water) / 1000 mL water
X = (105028) / 1000
X = 105.028 mg NaCl
Therefore, a 296 mL sample of this solution contains approximately 105 mg of NaCl.