221k views
3 votes
A concentration of 355 ppm NaCl in water means that there are 355 mg of NaCl in every liter of water. Determine how many mg of NaCl are present in a 296 mL sample of this solution.

1 Answer

6 votes

Final answer:

To find the amount of NaCl in a 296 mL sample of a 355 ppm solution, use the ratio 355 mg NaCl per 1000 mL to calculate that approximately 105 mg of NaCl would be present in the sample.

Step-by-step explanation:

To determine how many mg of NaCl are present in a 296 mL sample of a solution with a concentration of 355 ppm NaCl, we can use a proportional calculation. Since 355 ppm means there are 355 mg of NaCl in every liter (1000 mL) of water, we can set up a ratio to find the amount in 296 mL:

355 mg NaCl / 1000 mL water = X mg NaCl / 296 mL water

Solving for X gives us:

X = (355 mg NaCl × 296 mL water) / 1000 mL water

X = (105028) / 1000

X = 105.028 mg NaCl

Therefore, a 296 mL sample of this solution contains approximately 105 mg of NaCl.

User Dzhu
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.