Question

0.27 mol of argon gas is admitted to an evacuated 80 cm3 container at 20°C. The gas then undergoes an isochoric heating to a temperature of 500 OC What is the final pressure of the gas?

Answer 1

The final pressure of argon gas after isochoric heating to 500°C is calculated using the ideal gas law, which yields a final pressure of 231.808 atm.

Step-by-step explanation:

To determine the final pressure of argon gas after isochoric heating, we can use the ideal gas law formula P1/T1 = P2/T2, assuming the volume remains constant and the gas behaves ideally. Given that the initial temperature (T1) is 20°C (293 K), the final temperature (T2) is 500°C (773 K), and the initial pressure can be found using the initial conditions with the ideal gas law (P1V1 = nRT1).

To find the initial pressure P1, we use P1V1 = nRT1:

P1 = (nRT1) / V1

P1 = (0.27 mol × 0.0821 L·atm/K·mol × 293 K) / 0.080 L

P1 = 87.99975 atm

Now, using the temperature ratio, we can find the final pressure P2:

P2 = P1 × (T2 / T1)

P2 = 87.99975 atm × (773 K / 293 K)

P2 = 231.808 atm

So, the final pressure of the argon gas after isochoric heating to 500°C is 231.808 atm.