Final answer:
The boiling point of a 0.222 m aqueous solution of sucrose can be calculated using the formula ΔTb = kb * m, where ΔTb is the boiling point elevation, kb is the molal boiling point elevation constant for water, and m is the molality of the solution. By substituting the given values into the formula, we find that the boiling point elevation is 0.113664 ˚C. Adding this to the boiling point of water, we get a new boiling point of 100.113664 ˚C.
Step-by-step explanation:
The boiling point of a solution can be calculated using the formula:
ΔTb = kb * m
Where ΔTb is the boiling point elevation, kb is the molal boiling point elevation constant for water, and m is the molality of the solution.
In this case, we are given a 0.222 m aqueous solution of sucrose. By substituting the values into the formula, we can calculate the boiling point elevation:
ΔTb = 0.512˚C/m * 0.222 m = 0.113664 ˚C
To find the boiling point of the solution, we add the boiling point elevation to the boiling point of water:
New boiling point = 100.00 ˚C + 0.113664 ˚C = 100.113664 ˚C