Final answer:
To find the number of moles of O2 needed to react with 1.2 mol of NH3, use the ratio from the balanced equation (2NH3:3O2), resulting in 1.8 moles of O2 required.
Step-by-step explanation:
To calculate how many moles of O2 are needed to react with 1.2 mol of NH₃, we will use the mole ratio from the balanced equation provided:
2NH₃(g) + 3O₂(g) + 2CH₄(g) → 2HCN(g) + 6H₂O(g)
This equation tells us that 2 moles of NH₃ require 3 moles of O₂ to react completely. Therefore, we can set up a proportion:
- The ratio of NH₃ to O₂ in the equation is 2:3.
- For 1.2 mol of NH₃, we use the cross multiplication method to find the moles of O₂ needed:
(NH₃/O₂) = (1.2 mol NH₃ / x mol O₂) = (2/3)
Cross multiplying gives us: 2x = 1.2 × 3
2x = 3.6
Dividing both sides by 2:
x = 3.6 / 2
x = 1.8
Therefore, 1.8 moles of O₂ are needed to react completely with 1.2 moles of NH₃.