Question

You have sampled a population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%. Using that 36%, calculate the frequency of the "aa" genotype.. Assume Hardy-Weinberg equilibrium.

Answer 1

To calculate the frequency of the 'aa' genotype, use the Hardy-Weinberg equation: p^2 + 2pq + q^2 = 1. In this case, the percentage of the homozygous recessive genotype (aa) is 36%, so the frequency of the 'aa' genotype is 36%.

Step-by-step explanation:

To calculate the frequency of the 'aa' genotype, we can use the Hardy-Weinberg equation: p^2 + 2pq + q^2 = 1, where p is the frequency of the dominant allele and q is the frequency of the recessive allele. In this case, the percentage of the homozygous recessive genotype (aa) is 36%. The frequency of the recessive allele (q) is the square root of 36% (0.36), which is approximately 0.6. The frequency of the homozygous recessive genotype (aa) is q^2, so it would be 0.6^2 = 0.36, or 36%.