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Silver (I) can form a precipitate and/or a complex ion when it is mixed with sodium chloride, depending on the concentration of chloride ion present in the solution.

Write the reaction for the formation of the complex ion and the reaction for the formation of the precipitate.

User Fabio Buda
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Final answer:

When silver (I) is mixed with sodium chloride, it can form a precipitate or a complex ion depending on the concentration of chloride ions in the solution. The reaction for the formation of the precipitate is NaCl + AgNO3 → NaNO3 + AgCl. The formation of the complex ion can be represented by the equation AgCl(s) + H₂O(1) ⇌ Ag+(aq) + Cl- (aq).

Step-by-step explanation:

When silver (I) is mixed with sodium chloride, it can form a precipitate or a complex ion depending on the concentration of chloride ions in the solution.

The reaction for the formation of the precipitate is: NaCl + AgNO3 → NaNO3 + AgCl. This reaction produces a white precipitate of silver chloride.

On the other hand, the formation of the complex ion can be represented by the equation: AgCl(s) + H₂O(1) ⇌ Ag+(aq) + Cl- (aq). This indicates that solid silver chloride can dissolve and dissociate to form aqueous silver and chloride ions.

User Pypyodbc
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