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What is an equation of the line that passes through the point (3,−3) and is parallel to the line 152x 3y=15?

User SpankMe
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Final answer:

To find the equation of a line parallel to a given line, we need to determine its slope and use the point-slope form of a linear equation.

Step-by-step explanation:

To find the equation of a line that is parallel to the line 152x - 3y = 15, we need to determine its slope. The given line can be rewritten in slope-intercept form as y = (152/3)x - 5. To be parallel to this line, the slope of the new line must be the same. Therefore, the slope of the new line is 152/3.

Using the point-slope form of a linear equation, we can write the equation as y + 3 = (152/3)(x - 3). Simplifying further, we get y + 3 = (152/3)x - 152. Now, isolate y to get the final equation as y = (152/3)x - 155.

User Baldewin
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