Final answer:
The solutions to the quadratic equation a2 − 28a + 192 = 0 are x = 16 and x = 12, found by applying the quadratic formula without the need for rounding.
Step-by-step explanation:
To solve the quadratic equation a2 − 28a + 192 = 0 using the quadratic formula, we first identify the coefficients of the equation which are a = 1, b = -28, and c = 192. The quadratic formula is given by x = (-b ± √(b2 - 4ac)) / (2a). Applying this formula, we have:
x = (28 ± √((-28)2 - 4*1*192)) / (2*1)
x = (28 ± √(784 - 768)) / 2
x = (28 ± √16) / 2
x = (28 ± 4) / 2
So the two possible solutions for x are:
x = (28 + 4) / 2 = 32 / 2 = 16
and
x = (28 - 4) / 2 = 24 / 2 = 12
Therefore, the solutions to the equation are x = 16 and x = 12. We do not need to round as the solutions are exact whole numbers.