Question

A chemist has one solution that is 80% acid and another solution that is 30% acid. How much of the first solution is needed to make a 400 L solution that is 62% acid?

a) 200 L
b) 250 L
c) 300 L
d) 350 L

Answer 1

To make a 400 L solution that is 62% acid, 250 L of the first solution is needed.

Step-by-step explanation:

To determine how much of the first solution is needed to make a 400 L solution that is 62% acid, we can set up an equation using the principle of mass percentage. Let x represent the volume of the first solution in liters.

The total amount of acid in the final solution is the sum of the acid from each solution. The equation becomes: 0.8x + 0.3(400 - x) = 0.62(400)

Simplifying the equation and solving for x, we find that x = 250 L.