212k views
3 votes
What are the values of x in the equation x² - 6x + 9 = 25?

a.x=-2 or x = 8
b.x=-1 or x=-11
c.x = 1 or x = 11
d.x= 2 or x = -8

User Upog
by
7.8k points

1 Answer

5 votes

Final answer:

To solve the equation x² - 6x + 9 = 25, we rearrange it to x² - 6x - 16 = 0 and apply the quadratic formula, resulting in two solutions for x: x = 8 and x = -2.

Step-by-step explanation:

To find the values of x in the equation x² - 6x + 9 = 25, we first need to rearrange it into standard quadratic form ax² + bx + c = 0. Subtracting 25 from both sides of the equation gives us x² - 6x - 16 = 0. We can then solve this equation using the quadratic formula, x = [-b ± √(b² - 4ac)]/(2a), where a = 1, b = -6, and c = -16.

Plugging these values into the formula, we get:

  • x = [6 ± √(36 + 64)]/2
  • x = [6 ± √100]/2
  • x = [6 ± 10]/2

This yields two solutions:

  • x = (6 + 10)/2 = 16/2 = 8
  • x = (6 - 10)/2 = -4/2 = -2

Therefore, the values of x are x = 8 and x = -2.

User Come
by
8.0k points