Final answer:
The remainder of (2x²+7x-39)/(x-7) is 108.
Step-by-step explanation:
To find the remainder of the division (2x²+7x-39)/(x-7), polynomial long division or synthetic division can be used. Let's proceed with polynomial long division:
When dividing 2x² by x, we get 2x, which we then multiply by (x-7) to get (2x²-14x). Substracting this from (2x²+7x-39) leaves us with (21x-39). Now we divide 21x by x getting 21, and multiply the divisor by 21 to get (21x-147). Substracting this from our new polynomial, we end up with the remainder 108.