Question

What is the molality a 4.0 m naoh solution? the density of the solution is 1.04 g/ml.

Answer 1

The molality of a 4.0 m NaOH solution can be calculated using the formula: Molality (m) = moles of solute / mass of solvent (kg). In this case, the moles of NaOH can be calculated by converting the mass of NaOH to moles using the molar mass of NaOH, which is 40.0 g/mol. The mass of solvent can be calculated by dividing the mass of the solution by its density. Therefore, the molality of the 4.0 m NaOH solution is 1.04 m.

Step-by-step explanation:

The molality of a 4.0 m NaOH solution can be calculated using the formula:

Molality (m) = moles of solute / mass of solvent (kg)

In this case, the moles of NaOH can be calculated by converting the mass of NaOH to moles using the molar mass of NaOH, which is 40.0 g/mol. The mass of solvent can be calculated by dividing the mass of the solution by its density.

Let's calculate it:

1. Mass of NaOH = 4.0 g
2. Molar mass of NaOH = 40.0 g/mol
3. Mass of solution = 100 g
4. Density of solution = 1.04 g/mL

First, we need to convert the mass of NaOH to moles:

Moles of NaOH = 4.0 g / 40.0 g/mol = 0.1 mol

Next, we need to calculate the mass of the solvent:

Mass of solvent = Mass of solution - Mass of solute

Mass of solvent = 100 g - 4.0 g = 96.0 g

Finally, we can calculate the molality:

Molality (m) = 0.1 mol / 0.096 kg = 1.04 m