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Between what two consecutive interger does the larger solutiom to the equation -x^2 6x 5=0 lie?

User RogerParis
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Final answer:

The larger solution to the equation -x^2 + 6x + 5 = 0 lies between the consecutive integers -7 and -6, which is found by using the values in the quadratic formula.

Step-by-step explanation:

The given equation is -x^2 + 6x + 5 = 0. The quadratic formula is used to solve equations in the form ax^2 + bx + c = 0. For the given equation, a = -1, b = 6, and c = 5. The quadratic formula is x = (-b ± √(b^2 - 4ac)) / (2a). Substituting the values into the formula:

  • x = (6 ± √((6)^2 - 4(-1)(5))) / (2(-1))
  • x = (6 ± √(36 + 20)) / (-2)
  • x = (6 ± √56) / (-2)
  • x = (6 ± 7.483) / (-2)

Considering the larger solution, we have:

  • x = (6 + 7.483) / (-2)
  • x = 13.483 / (-2)
  • x = -6.7415

This indicates that the larger solution to the equation lies between the consecutive integers -7 and -6.

User Kodemi
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8.3k points

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