Final answer:
To find the number of carbon atoms in 47.6 g of Al2(CO3)3, calculate the moles using the molar mass and multiply by Avogadro's number. This yields approximately 3.673 × 1023 carbon atoms.
Step-by-step explanation:
The subject of this question is Chemistry, specifically stoichiometry and atomic theory. To determine how many atoms of carbon are contained in 47.6 g of Al2(CO3)3, we first need to calculate the number of moles in 47.6 g of Al2(CO3)3 using its molar mass. Afterward, we will use Avogadro's number to find the total number of carbon atoms.
Calculating the moles of Al2(CO3)3 in 47.6 g:
Moles of Al2(CO3)3 = Mass (g) / Molar Mass (g/mol)
= 47.6 g / 233.99 g/mol
= 0.2033 mol (rounded to four significant figures)
Each mole of Al2(CO3)3 contains 3 moles of CO32- ions.
Moles of CO32- ions = 0.2033 mol Al2(CO3)3 × 3 mol CO32-/mol Al2(CO3)3
= 0.6099 mol CO32- (rounded to four significant figures)
Each CO32- ion contains one atom of carbon, so:
Atoms of carbon = Moles of CO32- × Avogadro's number
= 0.6099 mol × 6.022 × 1023 atoms/mol
= 3.673 × 1023 atoms of carbon (rounded to four significant figures)
Therefore, there are approximately 3.673 × 1023 carbon atoms in 47.6 g of Al2(CO3)3.