Final answer:
For a 0.980 M solution of Calcium chloride, approximately 73.42 grams are needed to make 675 mL of the solution.
Step-by-step explanation:
To calculate the number of grams needed to make a 0.980 M solution of Calcium chloride, we need to use the formula:
moles = molarity * volume
First, we need to convert mL to L: 675 mL = 0.675 L
Next, we can rearrange the formula to solve for moles:
moles = 0.980 M * 0.675 L = 0.6615 mol
Finally, we can calculate the mass of Calcium chloride using its molar mass (110.98 g/mol):
mass = moles * molar mass = 0.6615 mol * 110.98 g/mol = 73.42 g
Therefore, approximately 73.42 grams of Calcium chloride are needed to make 675 mL of a 0.980 M solution.