Question

A 9.5 kg outdoor copper sculpture heats up during the day from 24°C to 78°C. How much energy was absorbed? Note: Copper has a specific heat of 390 J/kg °C.

a) 1,053,000 J
b) 2,275,000 J
c) 5,490 J
d) 10,780 J

Answer 1

The energy absorbed by a 9.5 kg copper sculpture when it heats from 24°C to 78°C is calculated using the formula Q = mcΔT. With a specific heat capacity of 390 J/kg °C for copper, the correct energy absorbed is 199,170 J. There is a discrepancy as none of the provided answer choices match this correct calculation.

Step-by-step explanation:

When a 9.5 kg outdoor copper sculpture heats up from 24°C to 78°C, the amount of energy absorbed can be calculated using the specific heat capacity formula: Q = mcΔT, where Q is the heat absorbed, m is the mass, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

For copper, the specific heat is given as 390 J/kg °C, the mass (m) is 9.5 kg, and the change in temperature (ΔT) is 78°C - 24°C = 54°C. Using these values:

Q = 9.5 kg × 390 J/kg °C × 54°C

Q = 9.5 × 390 × 54

Q = 199,170 J

However, none of the answer choices provided match the correct calculation of 199,170 J. There could have been an error in the given choices or the calculations.