Final answer:
The equation of a line perpendicular to y=5x+3 and passing through the point (2,4) would have a slope of -1/5. After using the point-slope form, the correct equation is y = (1/5)x + 22/5. Therefore, none of the provided options (A, B, C, D) is correct.
Step-by-step explanation:
To find the equation of a line that is perpendicular to y=5x+3 and passes through the point (2,4), we first need to identify the slope of the given line. The slope of the given line is 5. For a line to be perpendicular to this, its slope must be the negative reciprocal. The negative reciprocal of 5 is -1/5. Now we use the point-slope form to find the equation of the line that passes through (2,4) with a slope of -1/5:
y - y1 = m(x - x1)
Plugging in the values we have:
y - 4 = (-1/5)(x - 2)
Multiplying through by 5 to get rid of the fraction, we get:
5(y - 4) = -1(x - 2)
Distribute and simplify:
5y - 20 = -x + 2
Add 20 to both sides and x to both sides:
5y = x + 22
Divide everything by 5 to solve for y:
y = (1/5)x + 22/5
Therefore, the correct equation that is perpendicular to y=5x+3 and passes through the point (2,4) is not found among the options provided (A, B, C, D). None of the options match y = (1/5)x + 22/5.