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If I have two water containers, one is at 150 degrees and the other is 80 degrees, what will be the equilibrium temperature? (Room temp. is 72)

a) 112 degrees
b) 115 degrees
c) 120 degrees
d) 125 degrees

User Thurizas
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1 Answer

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Final answer:

The equilibrium temperature between the two water containers is 115 degrees.

Step-by-step explanation:

To determine the equilibrium temperature, you can use the concept of heat transfer. In this case, you have two water containers at different temperatures. Heat will transfer from the container at 150 degrees to the container at 80 degrees until both reach the equilibrium temperature.

The equilibrium temperature can be found using the formula:

Equilibrium temperature = (Temperature of Container 1 * Mass of Container 1 + Temperature of Container 2 * Mass of Container 2) / (Mass of Container 1 + Mass of Container 2)

Substituting the given values, the equilibrium temperature is:

Equilibrium temperature = (150 * 1 + 80 * 1) / (1 + 1) = 115 degrees

Therefore, the correct answer is 115 degrees (option b).