Final answer:
12.7 moles of lithium reacting with Calcium Fluoride would produce 12.7 moles of lithium fluoride, following a 2:1 stoichiometric ratio between lithium and lithium fluoride.
Step-by-step explanation:
When 12.7 moles of lithium react with Calcium Fluoride (CaF2), we need to consider the chemical reaction involved. Lithium (Li) reacts with calcium fluoride in a 2:1 molar ratio, according to the reaction:
2 Li + CaF2 → 2 LiF + Ca
Given the stoichiometry of the reaction, for every mole of CaF2 reacted, two moles of LiF are produced. Since we have 12.7 moles of lithium available for the reaction, we can expect 12.7 moles of lithium to produce 12.7 moles of lithium fluoride (LiF), assuming there is sufficient calcium fluoride present for all the lithium to react.