49.8k views
2 votes
Pls help asap !!

19 - DG

20 - Perimeter of JLNQ

work needs to be shown !!

Pls help asap !! 19 - DG 20 - Perimeter of JLNQ work needs to be shown !!-example-1
User Cygery
by
7.2k points

1 Answer

7 votes

1. The value of DG is 9

2. The perimeter of the shape is 34

1. Since the centre of the circle is G. The radius of a circle is the line form the center to any part of the circumference.

Therefore;

GF and DG are both radii

DG = GF

therefore

DG = x - 2

To find the value of x

2x - 4 = x + 7

2x - x = 7 + 4

x = 11

DG = 11-2 = 9

2. NP = 2

KL = 5

JR = 3

QP = 7

this is because the tangents of a circle from the same point on the circle are equal

Perimeter = 9 + 7 + 8 + 10

= 34

User Kaoutar
by
7.6k points