Final answer:
The object will move approximately 0.119 meters farther from its current position before stopping momentarily and changing direction.
Step-by-step explanation:
To find how much farther the object will move before it stops momentarily and then starts moving back to the left, we need to analyze the given information. When the object is displaced 0.555 m to the right, it has a velocity of 2.50 m/s to the right and an acceleration of 8.40 m/s^2 to the left.
Since the velocity and acceleration have opposite directions, we know that the object is slowing down. When the object stops momentarily, its velocity will be zero. To calculate the distance it travels before stopping, we can use the equation of motion:
v² = u² + 2as
Where v is the final velocity (0 m/s in this case), u is the initial velocity (2.50 m/s to the right), a is the acceleration (-8.40 m/s^2), and s is the displacement from the starting point.
We can rearrange the equation to solve for the displacement:
s = (v² - u²) / (2a)
Plugging in the values, we get:
s = (0² - (2.50)²) / (2(-8.40))
Simplifying the equation, we find that the object will move approximately 0.119 meters farther to the right before stopping momentarily and changing direction.