Question

PLEASE I NEED ANSWERD OF D AND E

d) find the power cunsumption in 22 ohms lamp and 4.5 ohms lamp ?

e) find the power delivered by the battery

Answer 1

Step-by-step explanation:

Given:

R₁ = 22 Ω

R₂ = 4.5 Ω

U = 45 V

_________

I - ?

P₁ - ?

P₂ - ?

P - ?

Circuit resistance:

R = R₁ + R₂ = 22 + 4.5 = 26.5 Ω

Circuit current:

I = I₁ = I₂ = U / R = 45 / 26.5 ≈ 1.7 А

Lamp voltages:

U₁ = I₁·R₁ = 1.7·22 ≈ 37.40 V

U₂ = I₂·R₂ = 1.7·4.5 ≈ 7.65 V

Power:

P₁ = U₁·I₁ = 37.40·1.7 ≈ 63.6 W

P₂ = U₂·I₂ = 7.65·1.7 ≈ 13.0 W

P = U·I = 45·1.7 ≈ 76.5 W

Answer 2

2) find the power rating of the given transformer:

the transformer is rated at 250v,50hz, and it is used with a circuit which

consists of a 200v,50hz d.c. source and a rheostat.the rheostat is used to control the current in the primary of the transformer.the maximum readable current in the primary of the transformer is 250mA.the transformer is wired as an autotransformer with the primary winding of 250 turns and the secondary winding of 250 turns.the current in the secondary winding of the transformer is to be kept at 10mA when the load current in the rheostat is 10mA.

3) a single phase a.c. supply of 230v,50hz is connected across a series combination of a capacitor and a resistor in parallel with a pure inductor.the resistor and inductor are connected in series with each other.the impedance of the inductor is 100 ohms and the impedance of the capacitor is 60 ohms.the supply current is 10A.

a) find the impedance of the capacitor if the power factor of the circuit is 0.8 lagging.

b

Step-by-step explanation: