Question

State the minimum or maximum value of the function f(x) = -x^2 + 3x - 2 as a decimal.

a) -2.75
b) -1.25
c) 0.75
d) 2.75

Answer 1

To find the minimum or maximum value of the function f(x) = -x^2 + 3x - 2, we can use the vertex formula. The minimum or maximum value of the function is 0.25.

Step-by-step explanation:

To find the minimum or maximum value of the function f(x) = -x^2 + 3x - 2, we can use the vertex formula. The vertex formula states that the x-coordinate of the vertex of a quadratic function in the form ax^2 + bx + c is given by x = -b/2a. In this case, a = -1, b = 3, and c = -2. Plugging these values into the formula, we get x = -3/2*(-1) = 3/2 = 1.5.

Substituting this x-value back into the function, we get f(1.5) = -1.5^2 + 3(1.5) - 2 = -2.25 + 4.5 - 2 = 0.25.

Therefore, the minimum or maximum value of the function is 0.25.