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In ACDE, the measure of ∠E is 90°, the measure of ∠C is 16°, and EC = 65 feet. Find the length of DE to the nearest tenth of a foot.

a. 58.5 feet
b. 56.5 feet
c. 62.2 feet
d. 59.1 feet

1 Answer

2 votes

Final answer:

Using the cosine function cos(16°) = DE / 65, we find that DE is approximately 62.5 feet to the nearest tenth.

Step-by-step explanation:

To find the length of DE, we can use trigonometric functions, specifically the cosine function, since we have an angle and the hypotenuse of a right triangle ECDE with ∠E being 90° and ∠C being 16°. The length of DE represents the adjacent side to ∠C, and EC is the hypotenuse.

The formula using the cosine function is:

cos(C) = adjacent / hypotenuse

Plugging in the values we have:

cos(16°) = DE / 65 feet

Now we can solve for DE:

DE = 65 feet * cos(16°)

Calculating this using a calculator:

DE ≈ 65 feet * 0.9613 ≈ 62.4845 feet

Round to the nearest tenth:

DE ≈ 62.5 feet

Therefore, the length of DE to the nearest tenth of a foot is 62.5 feet.

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